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            • 1.

              \((1)\)已知各项均为正数的等比数列\(\{a_{n}\}\)满足\(a_{7}=a_{6}+2a_{5}\),若存在两项\(a_{m}\),\(a_{n}\)使得\( \sqrt{a_{m}a_{n}}=4a_{1}\),则\( \dfrac{1}{m}+ \dfrac{4}{n}\)的最小值为_____________.


              \((2)S_{n}\)为数列\(\{a_{n}\}\)的前\(n\)项和\(.\)已知\(a_{n} > 0\),\(a\rlap{_{n}}{^{2}}+2a_{n}=4S_{n}+3\).

                \(①\)求\(\{a_{n}\}\)的通项公式;     

              \(②\)设\(b_{n}= \dfrac{1}{a_{n}a_{n+1}}\),求数列\(\{b_{n}\}\)的前\(n\)项和.

            • 2. 在等比数列\(\{ \)\(a_{n}\)\(\}\)中,若        
            • 3. 已知递增等比数列\(\{a_{n}\}\)满足:\(a_{2}+a_{3}+a_{4}=28\),且\(a_{3}+2\)是\(a_{2}\)和\(a_{4}\)的等差中项,
              \((\)Ⅰ\()\) 求数列\(\{a_{n}\}\)的通项公式;
              \((\)Ⅱ\()\)若\(b_{n}=a_{n}\log _{ \frac {1}{2}}a_{n}\),\(S_{n}=b_{1}+b_{2}+…+b_{n}\),求使\(S_{n}+n⋅2^{n+1} > 62\)成立的正整数\(n\)的最小值.
            • 4.
              等比数列\(\{a_{n}\}\)中,\(a_{5}=4\),则\(a_{2}⋅a_{8}=(\)  \()\)
              A.\(4\)
              B.\(8\)
              C.\(16\)
              D.\(32\)
            • 5.

              已知各项均为正数的数列\(\{a_{n}\}\)的首项\(a_{1}=1\),\(S_{n}\)是数列\(\{a_{n}\}\)的前\(n\)项和,且满足:\(a_{n}S_{n+1}-a_{n+1}S_{n}+a_{n}-a_{n+1}=λa_{n}a_{n+1}(λ\neq 0,n∈N^{*}).\)

              \((1)\) 若\(a_{1}\),\(a_{2}\),\(a_{3}\)成等比数列,求实数\(λ\)的值\(;\)

              \((2)\) 若\(λ=\dfrac{1}{2}\),求\(S_{n}\).

            • 6. 若\(a\),\(b\)是函数\(f(x)=x^{2}-px+q(p > 0,q > 0)\)的两个不同的零点,且\(a\),\(b\),\(-2\)这三个数可适当排序后成等差数列,也可适当排序后成等比数列,则\(p+q\)的值等于\((\)  \()\)
              A.\(6\)
              B.\(7\)
              C.\(8\)
              D.\(9\)
            • 7.

              已知数列\(\{ a_{n}\}\)的前\(n\)项和为\(S_{n}{,}a_{1}{=}\dfrac{1}{2}{,}2a_{n{+}1}{=}S_{n}{+}1\).

              \((\)Ⅰ\()\)求\(a_{2}{,}a_{3}\)的值;

              \((\)Ⅱ\()\)设\(b_{n}{=}2a_{n}{-}2n{-}1\),求数列\(\{ b_{n}\}\)的前\(n\)项和\(T_{n}\).

            • 8. 公差不为零的等差数列\(\{a_{n}\}\)的前\(n\)项和为\(S_{n}.\)若\(a_{4}\)是\(a_{3}\)与\(a_{7}\)的等比中项,\(S_{8}=16\),则\(S_{10}\)等于(    )
              A.\(18\)     
              B.\(24\)     
              C.\(30\)     
              D.\(60\)
            • 9.

              已知各项都为正的等差数列\(\left\{ {{a}_{n}} \right\}\)中,若\({{a}_{2}}+{{a}_{3}}+{{a}_{4}}=15\),若\({{a}_{1}}+2\),\({{a}_{3}}+4\),\({{a}_{6}}+16\)成等比数列,则\({{a}_{10}}=\)

              A.\(19\)
              B.\(20\)
              C.\(21\)
              D.\(22\) 
            • 10.

              已知数列\(\{\)\(a_{n}\)\(\}\)的前\(n\)项和为\(S_{n}\),且\(S_{n}=a_{n+}\)\({\,\!}_{1}\)\(+n-\)\(2\),\(n\)\(∈N\)\({\,\!}^{*}\)\(a\)\({\,\!}_{1}\)\(=\)\(2\)

              \((1)\)证明:数列\(\{\)\(a_{n}-\)\(1\}\)是等比数列,并求数列\(\{\)\(a_{n}\)\(\}\)的通项公式\(;\)

              \((2)\)设\(b_{n}=\)\( \dfrac{3n}{{S}_{n}-n+1} (\)\(n\)\(∈N\)\({\,\!}^{*}\)\()\)的前\(n\)项和为\(T_{n}\),证明:\(T_{n} < \)\(6\)

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