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            • 1.
              在等比数列\(\{a_{n}\}\)中,若\(a_{4}\),\(a_{8}\)是方程\(x^{2}-4x+3=0\)的两根,则\(a_{6}\)的值是\((\)  \()\)
              A.\(± \sqrt {3}\)
              B.\(- \sqrt {3}\)
              C.\( \sqrt {3}\)
              D.\(±3\)
            • 2.
              设\(S_{n}\)是等比数列\(\{a_{n}\}\)的前\(n\)项和,\(S_{4}=5S_{2}\),则\( \dfrac {a_{3}\cdot a_{8}}{a_{5}^{2}}\)的值为\((\)  \()\)
              A.\(-2\)或\(-1\)
              B.\(1\)或\(2\)
              C.\(±2\)或\(-1\)
              D.\(±1\)或\(2\)
            • 3.
              在等比数列\(\{a_{n}\}\)中,若\(a_{4}a_{5}a_{6}=27\),则\(a_{1}a_{9}=(\)  \()\)
              A.\(3\)
              B.\(6\)
              C.\(27\)
              D.\(9\)
            • 4.
              等比数列\(\{a_{n}\}\)中,\(a_{4}=2\),\(a_{5}=5\),则数列\(\{\lg a_{n}\}\)的前\(8\)项和等于 ______ .
            • 5.
              已知各项均为正数的等比数列\(\{a_{n}\}\),其前\(n\)项和\(S_{n}\),若\(S_{n}=2\),\(S_{3n}=14\),则\(S_{6n}=\) ______ .
            • 6.
              已知数列\(\{a_{n}\}\)的各项均为正数,其前\(n\)项和为\(S_{n}\),且满足\(a_{1}=1\),\(a_{n+1}=2 \sqrt {S_{n}}+1\),\(n∈N^{*}\).
              \((1)\)求\(a_{2}\)的值;
              \((2)\)求数列\(\{a_{n}\}\)的通项公式;
              \((3)\)是否存在正整数\(k\),使\(a_{k}\),\(S_{2k-1}\),\(a_{4k}\)成等比数列?若存在,求\(k\)的值,若不存在,请说明理由.
            • 7.
              记等比数列\(\{a_{n}\}\)的前\(n\)项积为\(T_{n}(n∈N^{*})\),已知\(a_{m-1}a_{m+1}-2a_{m}=0\),且\(T_{2m-1}=128\),则\(m=\) ______
            • 8.
              等比数列\(\{a_{n}\}\)中,\(S_{n}\)表示前\(n\)顶和,\(a_{3}=2S_{2}+1\),\(a_{4}=2S_{3}+1\),则公比\(q\)为 ______ .
            • 9.
              若\(a_{1} > 0\),\(a_{1}\neq 1\),\(a_{n+1}= \dfrac {2a_{n}}{1+a_{n}}(n=1,2,…)\)
              \((1)\)求证:\(a_{n+1}\neq a_{n}\);
              \((2)\)令\(a_{1}= \dfrac {1}{2}\),写出\(a_{2}\)、\(a_{3}\)、\(a_{4}\)、\(a_{5}\)的值,观察并归纳出这个数列的通项公式\(a_{n}\);
              \((3)\)证明:存在不等于零的常数\(p\),使\(\{ \dfrac {a_{n}+P}{a_{n}}\}\)是等比数列,并求出公比\(q\)的值.
            • 10.
              已知正项数列\(\{a_{n}\}\)的前\(n\)和为\(S_{n}\),且\( \sqrt {S_{n}}\)是\( \dfrac {1}{4}\)与\((a_{n}+1)^{2}\)的等比中项.
              \((1)\)求证:数列\(\{a_{n}\}\)是等差数列;
              \((2)\)若\(b_{n}= \dfrac {a_{n}}{2^{n}}\),数列\(\{b_{n}\}\)的前\(n\)项和为\(T_{n}\),求\(T_{n}\).
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