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            • 1.

              设数列\(\left\{{a}_{n}\right\} \)的前\(n\)项和为\(S_{n}\),已知\({a}_{1}=2,{a}_{n+1}=2{S}_{n}+2\left(n∈{N}^{*}\right) \)

              \((1)\)求数列\(\left\{{a}_{n}\right\} \)通项公式;

              \((2)\)在\(a_{n}\)与\(a_{n+1}\)之间插入\(n\)个数,使这\(n+2\)个数组成一个公差为\(d_{n}\)的等差数列。

              \((\)Ⅰ\()\)求证:\(\dfrac{1}{{d}_{1}}+ \dfrac{1}{{d}_{2}}+ \dfrac{1}{{d}_{3}}+…+ \dfrac{1}{{d}_{n}} < \dfrac{15}{16}\left(n∈{N}^{*}\right) \)

              \((\)Ⅱ\()\)在数列\(\left\{{d}_{n}\right\} \)中是否存在三项\(d_{m}\),\(d_{k}\),\(d_{p}(\)其中\(m\),\(k\),\(p\)成等差数列\()\)成等比数列,若存在,求出这样的三项;若不存在,说明理由.

            • 2.
              已知数列\(\{a_{n}\}\)中,\(a_{2}=1\),前\(n\)项和为\(S_{n}\),且\(S_{n}= \dfrac {n(a_{n}-a_{1})}{2}\).
              \((1)\)求\(a_{1}\),\(a_{3}\);
              \((2)\)求证:数列\(\{a_{n}\}\)为等差数列,并写出其通项公式;
              \((3)\)设\(\lg b_{n}= \dfrac {a_{n+1}}{3^{n}}\),试问是否存在正整数\(p\),\(q(\)其中\(1 < p < q)\),使\(b_{1}\),\(b_{p}\),\(b_{q}\)成等比数列?若存在,求出所有满足条件的数组\((p,q)\);若不存在,说明理由.
            • 3.

              将\(25\)个数排成五行五列:己知第一行成等差数列,而每一列都成等比数列,且五个公比全相等,若\(a^{24}=4\),\(a_{41}=-2\),\(a_{43}=10\),则\(a_{11}×a_{55}\)的值为________.

            • 4. 已知等比数列\(\{a_{n}\}\)中,\(a_{2} > a_{3}=1\),则使不等式\((a_{1}- \dfrac {1}{a_{1}})+(a_{2}- \dfrac {1}{a_{2}})+(a_{3}- \dfrac {1}{a_{3}})+…+(a_{n}- \dfrac {1}{a_{n}})\geqslant 0\)成立的最大自然数\(n\)是 ______
            • 5.

              已知数列\(\left\{ {{a}_{n}} \right\}\)的前\(n\)项和为\(S_{n}\),且\(1\),\(a_{n}\),\(S_{n}\)成等差数列.

                  \((1)\)求数列\(\left\{ {{a}_{n}} \right\}\)的通项公式;

                  \((2)\)若数列\(\left\{ {{b}_{n}} \right\}\)满足\({{a}_{n}}\cdot {{b}_{n}}=1+2n{{a}_{n}}\),求数列\(\left\{ {{b}_{n}} \right\}\)的前\(n\)项和\({{T}_{n}}\).

            • 6.

              设\(S_{n}\)为等比数列\(\{ a_{n}\}\)的前\(n\)项和,若\(S_{1}{,}S_{3}{,}S_{2}\)成等差数列,则等比数列\(\{ a_{n}\}\)的公比\(q{=}({  })\)

              A.\({-}2\)
              B.\({-}1\)
              C.\({-}\dfrac{1}{2}\)
              D.\(\dfrac{1}{2}\)
            • 7.

              已知数列\(\{an\}\)的首项\({a}_{1}= \dfrac{3}{5},{a}_{n+1}= \dfrac{3{a}_{n}}{2{a}_{n}+1},n∈{N}^{*} \).

              \((1)\)求证:数列\(\{ \dfrac{1}{{a}_{n}}-1\} \)为等比数列;

              \((2)\)记\({S}_{n}= \dfrac{1}{{a}_{1}}+ \dfrac{1}{{a}_{2}}+...+ \dfrac{1}{{a}_{n}} \),若\(S_{n} < 101\),求最大正整数\(n\)的值;

                  \((3)\)是否存在互不相等的正整数\(m\),\(s\),\(n\),使\(m\),\(s\),\(n\)成等差数列,且\(a_{m}-1\),\(a_{s}-1\),\(a_{n}-1\)成等比数列?如果存在,请给予证明;如果不存在,请说明理由.

            • 8.
              成等差数列的三个正数的和等于\(6\),并且这三个数分别加上\(3\)、\(6\)、\(13\)后成为等比数列\(\{b_{n}\}\)中的\(b_{3}\)、\(b_{4}\)、\(b_{5}\),则数列\(\{b_{n}\}\)的通项公式为\((\)  \()\)
              A.\(b_{n}=2^{n-1}\)
              B.\(b_{n}=3^{n-1}\)
              C.\(b_{n}=2^{n-2}\)
              D.\(b_{n}=3^{n-2}\)
            • 9.

              已知公比不为\(1\)的等比数列\(\{a_{n}\}\)的首项\({{a}_{1}}=\dfrac{1}{2}\),前\(n\)项和为\(S_{n}\),且\(a_{4}+S_{4}\),\(a_{5}+S_{5}\),\(a_{6}+S_{6}\)成等差数列.

              \((1)\)求等比数列\(\{a_{n}\}\)的通项公式及前\(n\)项和\(S_{n}\);

              \((2)\)对\(n∈N^{*}\),在\(a_{n}\)与\(a_{n+1}\)之间插入\(3^{n}\)个数,使这\(3^{n}+2\)个数成等差数列,记插入的这\(3^{n}\)个数的和为\(b_{n}\),求数列\(\{b_{n}\}\)的前\(n\)项和\(T_{n}\).

            • 10. 已知数列\(\{a_{n}\}\)是等差数列,\(\{b_{n}\}\)是等比数列,且\(a_{1}=11\),\(b_{1}=1\),\(a_{2}+b_{2}=11\),\(a_{3}+b_{3}=11\).
              \((\)Ⅰ\()\)求数列\(\{a_{n}\}\)和\(\{b_{n}\}\)的通项公式;
              \((\)Ⅱ\()\)求数列\(\{|a_{n}-b_{n}|\}\)的前\(12\)项的和\(S_{12}\).
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