已知椭圆\(C\):\(\dfrac{{{x}^{2}}}{{{a}^{2}}}+\dfrac{{{y}^{2}}}{{{b}^{2}}}=1(a > b > 0)\)的焦距为\(2\sqrt{3}\),以椭圆右顶点\(A\)为圆心的圆与直线\(y=\dfrac{b}{a}x\)相交于\(P\),\(Q\)两点,且\(\overrightarrow{AP}\cdot \overrightarrow{AQ}=0\),\(\overrightarrow{OP}=3\overrightarrow{OQ}\).
\((1)\)求椭圆\(C\)的方程;
\((2)\)不过原点的直线\(l\)与椭圆\(C\)交于\(M\),\(N\)两点,直线\(OM\)、\(l\)、\(ON\)的斜率\(k_{1}\),\(k\),\(k_{2}\)成等比数列\(.\)记以\(OM\),\(ON\)为直径的圆的面积分别为\(S_{1}\),\(S_{2}\),求证:\(S_{1}+S_{2}\)为定值.