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            • 1.

              如图,在一个\({{60}^{o}}\)的二面角的棱上有两点\(A,B\),线段\(AC,BD\)分别在这两个面内,且都垂直于棱\(AB\),\(AB=AC=a\),\(BD=2a\),则\(CD\)的长为\((\)    \()\)  

              A.\(2a\)
              B.\(\sqrt{5}a\)
              C.\(a\)
              D.\(\sqrt{3}a\)
            • 2. 如图,四棱锥\(P-ABCD\)中,\(PD⊥\)平面\(ABCD\),底面\(ABCD\)是正方形,\(PD=AB=2\),\(E\)为\(PC\)中点.
              \((1)\)求证:\(DE⊥\)平面\(PCB\);
              \((2)\)求点\(C\)到平面\(DEB\)的距离;
              \((3)\)求二面角\(E-BD-P\)的余弦值.
            • 3.

              如图,菱形\(ABCD\)的对角线\(AC\)与\(BD\)交于点\(O\),\(AB=5,AC=6\),点\(E,F\)分别在\(AD,CD\)上,\(AE=CF=\dfrac{5}{4}\),\(EF\)交于\(BD\)于点\(H\),将\(\Delta DEF\)沿\(EF\)折到\(\Delta {{D}^{{{'}}}}EF\)的位置,\(O{{D}^{{{'}}}}=\sqrt{10}\).


              \((\)Ⅰ\()\)证明:\({{D}^{{{'}}}}H ⊥\)平面\(ABCD\);
              \((\)Ⅱ\()\)求二面角\(B-{{D}^{{{'}}}}A-C\)的正弦值.
            • 4.

              二面角\(α-\) \(l\)\(-β\)等于\(120^{\circ}\),\(A\)、\(B\)是棱 \(l\)上两点,\(AC\)、\(BD\)分别在半平面\(α\)、\(β\)内,\(AC⊥\) \(l\),\(BD⊥\) \(l\),且\(AB=AC=BD=1\),则\(CD\)的长等于(    )

              A.\( \sqrt{2} \)    
              B.\( \sqrt{3} \)      
              C.\(2\)      
              D.\( \sqrt{5} \)
            • 5. 如图,四棱柱\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,侧棱\(AA_{1}⊥\)底面\(ABCD\),\(AB/\!/DC\),\(AB⊥AD\),\(AD=CD=1\),\(AA_{1}=AB=2\),\(E\)为棱\(AA_{1}\)的中点.
              \((\)Ⅰ\()\)求证:\(B_{1}C_{1}⊥CE\);
              \((\)Ⅱ\()\)求二面角\(B_{1}-CE-C_{1}\)的正弦值.
            • 6.

              如图,正三棱柱\(ABC\)\(-\)\(A\)\({\,\!}_{1}\)\(B\)\({\,\!}_{1}\)\(C\)\({\,\!}_{1}\)的所有棱长都为\(2\),\(D\)\(CC\)\({\,\!}_{1}\)中点.

               

              \((1)\)求证:\(AB\)\({\,\!}_{1}⊥\)平面\(A\)\({\,\!}_{1}\)\(BD\)

                 \((2)\)求二面角\(A\)\(-\)\(A\)\({\,\!}_{1}\)\(D\)\(-\)\(B\)的余弦值;                 

              \((3)\)求点\(C\)\({\,\!}_{1}\)到平面\(A\)\({\,\!}_{1}\)\(BD\)的距离.

            • 7.
              将正方形\(ABCD\)沿对角线\(BD\)折成直二面角\(A-BD-C\),有如下四个结论:
              \(①AC⊥BD\);
              \(②\triangle ACD\)是等边三角形;
              \(③AB\)与平面\(BCD\)成\(60^{\circ}\)的角;
              \(④AB\)与\(CD\)所成的角为\(60^{\circ}\);
              其中正确结论是____________\((\)写出所有正确结论的序号\()\)
            • 8.

              如图,在多面体,\(ABCDEF\)中,底面\(ABCD\)是边长为\(2\)的菱形,\(∠BDC=60^{\circ}\),四边形\(BDEF\)是矩形,平面\(BDEF⊥\)平面\(ABCD\),\(BF=3\),\(H\)是\(CF\)的中点.

              \((1)\)求证\(AC⊥\)平面\(BDEF\);

              \((2)\)求直线\(DH\)与平面\(BDEF\)所成角的正弦值;

              \((3)\)求二面角\(H—BD—C\)的大小.

            • 9. 如图,在四棱锥\(P-ABCD\)中,底面\(ABCD\)为直角梯形,\(AD/\!/BC\),\(∠ADC=90^{\circ}\),平面\(PAD⊥\)底面\(ABCD\),\(Q\)为\(AD\)的中点,\(M\)是棱\(PC\)上的点,\(PA=PD=2\),\(BC= \dfrac {1}{2}AD=1\),\(CD= \sqrt {3}\).
              \((1)\)求证:平面\(PQB⊥\)平面\(PAD\);
              \((2)\)若二面角\(M-BQ-C\)为\(30^{\circ}\),设\(PM=tMC\),试确定\(t\)的值.
            • 10.

              如图,在四棱锥\(P-ABCD\)中,底面\(ABCD\)是正方形,侧面\(PAD\bot \)底面\(ABCD\),\(E\),\(F\)分别为\(P{A}\),\(BD\)中点,\(PA=PD=AD=2\).

              \((\)Ⅰ\()\)求二面角\({E}-{DF}-{A}\)的余弦值;

              \((\)Ⅱ\()\)在棱\(P{C}\)上是否存在一点\(G\),使\(GF\bot \)平面\(EDF\)?若存在,指出点\(G\)的位置;若不存在,说明理由.

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