优优班--学霸训练营 > 知识点挑题
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            • 1.

              曲线\(y=\ln (2x-1)\)上的点到直线\(2x-y+3=0\)的最短距离是(    )

              A.\(2 \sqrt{5}\)              
              B.\( \sqrt{5}\)
              C.\(3 \sqrt{5}\)
              D.\(0\)
            • 2.

              设函数\(f\left( x \right)=\dfrac{3}{2}{{x}^{2}}-2ax(a > 0)\)与\(g\left( x \right)={{a}^{2}}\ln x+b\)有公共点,且在公共点处的切线方程相同,则实数\(b\)的最大值为_______.

            • 3.

              若曲线\(y={{x}^{-\frac{1}{2}}}\)在点\(\left(a,{a}^{- \frac{1}{2}}\right) \)处的切线与两个坐标轴围成的三角形的面积为\(18\),则\(a=\)  \((\)    \()\)

              A.\(64\)
              B.\(32\)
              C.\(16\)
              D.\(8\)
            • 4.

              下列说法正确的是(    )

              A.若\(f\prime \left( {{x}_{0}} \right)\)不存在,则曲线\(y=f(x) \)在点\(({x}_{0},f({x}_{0})) \)处就没有切线

              B.若曲线\(y=f(x) \)在点\(({x}_{0},f({x}_{0})) \)处有切线,则\(f\prime \left( {{x}_{0}} \right)\)必存在

              C.若\(f\prime \left( {{x}_{0}} \right)\)不存在,则曲线\(y=f(x) \)在点\(({x}_{0},f({x}_{0})) \)处的切线斜率不存在

              D.若曲线\(y=f(x) \)在点\(({x}_{0},f({x}_{0})) \)处的切线斜率不存在,则曲线在该点处就没有切线
            • 5.

              已知函数\(f(x)=(x-a){{e}^{x}}-\dfrac{1}{2}a{{x}^{2}}+a(a-1)x\),\((x∈R)\)

              \((1)\)若曲线\(y=f(x)\)在点\((0,f(0))\)处的切线为\(l\),\(l\)与\(x\)轴的交点坐标为\((2,0)\),求\(a\)的值;

              \((2)\)讨论\(f(x)\)的单调性.

            • 6.

              己知直线\(2x-y+1=0\)与曲线\(y=1nx+a\)相切,则实数\(a\)的值是________

            • 7.

              已知函数\(f(x)=x^{2}-\dfrac{a}{2}\ln x\)的图像在点\((\dfrac{1}{2},f\left( \dfrac{1}{2} \right))\)处的切线斜率为\(0\).

              \((1)\)讨论函数\(f(x)\)的单调性\(;\)

              \((2)\)若\(g(x)=f(x)+\dfrac{1}{2}mx\)在区间\((1,+∞)\)上没有零点 ,求实数\(m\)的取值范围.

            • 8.

              设点\(P\)、\(Q\)分别是曲线\(y=xe^{-x}(e\)是自然对数的底数\()\)和直线\(y=x+1\)上的动点,则\(P\)、\(Q\)两点间距离的最小值为\((\)  \()\)

              A.\( \dfrac{ \sqrt{2}}{2}\left( \left. 2- \dfrac{1}{e} \right. \right)\)
              B.\( \sqrt{2}\left( \left. 2- \dfrac{1}{e} \right. \right)\)
              C.\( \dfrac{ \sqrt{2}}{2}\)
              D.\( \sqrt{2}\)
            • 9. 已知函数\(f\left(x\right)=\ln x- \dfrac{1}{2}a{x}^{2}+x,a∈R \).
              \((1)\)当\(a=0\)时,求函数\(f(x)\)在\(\left(1,f\left(1\right)\right) \)处的切线方程;
              \((2)\)令\(g\left(x\right)=f\left(x\right)-\left(ax-1\right) \),求函数\(g(x)\)的极值;
              \((3)\)若\(a=-2\),正实数\(x_{1}\),\(x_{2}\)满足\(f\left({x}_{1}\right)+f\left({x}_{2}\right)+{x}_{1}{x}_{2}=0 \),证明:\({x}_{1}+{x}_{2}\geqslant \dfrac{ \sqrt{5}-1}{2} \).
            • 10.

              设函数\(f(x)=\begin{cases} & \ln x,x > 0 \\ & -2x-1,x\leqslant 0 \\ \end{cases}\) ,\(D\)是由\(x\)轴和曲线\(y=f(x)\)及该曲线在点\((1,0)\)处的切线所围成的封闭区域,则\(z=x-2y\)在\(D\)上的最大值为\((\)   \()\)

              A.\(1\)
              B.\(2\)
              C.\(3\)
              D.\(4\)
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