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            • 1.

              记\({{S}_{n}}\)为数列\(\{{{a}_{n}}\}\)的前\(n\)项和\(.\) 若\({{S}_{n}}=2{{a}_{n}}+1\),则\({{S}_{6}}=\)_________.

            • 2.
              已知数列\(\{{{a}_{n}}\}\) 满足\({{a}_{1}}=1\) \(n{{a}_{n+1}}=2(n+1){{a}_{n}}\) \(.\) 设\({{b}_{n}}=\dfrac{{{a}_{n}}}{n}\)
              \((1)\)求\({{b}_{1}}\) \({{b}_{2}}\) \({{b}_{3}}\)
              \((2)\)判断数列\(\{{{b}_{n}}\}\) 是否为等比数列,并说明理由;

              \((3)\)求\(\{{{a}_{n}}\}\)的通项公式.

            • 3.

              已知数列\(\{a_{n}\}\)的前\(n\)项和\(S_{n}=1+a\)\({S}_{n}=1+λ{a}_{n} \),其中\(\lambda \)\(0\)

              \((I)\)证明\(\{a\)\(n\)\(\}\)是等比数列,并求其通项公式

              \((II)\)若\({S}_{5}= \dfrac{31}{32} \) ,求\(\lambda \)

            • 4.

              已知\(\left\{ {{a}_{n}} \right\}\)是公差为\(3\)的等差数列,数列\(\left\{ {{b}_{n}} \right\}\)满足\({{b}_{1}}=1,{{b}_{2}}=\dfrac{1}{3},{{a}_{n}}{{b}_{n+1}}+{{b}_{n+1}}=n{{b}_{n}}\) .

               \((1)\)求\(\left\{ {{a}_{n}} \right\}\)的通项公式;

              \((2)\)求\(\left\{ {{b}_{n}} \right\}\)的前\(n\)项和。

            • 5. 已知{an}是等差数列,公差d>0,Sn是其前n项和,a1a4=22,S4=26.
              (1)求数列{an}的通项公式;
              (2)令,数列{bn}的前n项和为Tn,求证:
            • 6.
              设数列\(\{a_{n}\}\)满足\(a_{1}+3a_{2}+…+(2n-1)a_{n}=2n\).
              \((1)\)求\(\{a_{n}\}\)的通项公式;
              \((2)\)求数列\(\{ \dfrac {a_{n}}{2n+1}\}\)的前\(n\)项和.
            • 7.
              已知\(\{a_{n}\}\)为等差数列,前\(n\)项和为\(S_{n}(n∈N^{+})\),\(\{b_{n}\}\)是首项为\(2\)的等比数列,且公比大于\(0\),\(b_{2}+b_{3}=12\),\(b_{3}=a_{4}-2a_{1}\),\(S_{11}=11b_{4}\).
              \((\)Ⅰ\()\)求\(\{a_{n}\}\)和\(\{b_{n}\}\)的通项公式;
              \((\)Ⅱ\()\)求数列\(\{a_{2n}b_{2n-1}\}\)的前\(n\)项和\((n∈N^{+}).\)
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