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            • 1.
              已知数列\(\{a_{n}\}\)的前\(n\)项和为\(S_{n}\),若\(S_{n}=n^{2}+5n\).
              \((1)\)证明数列\(\{a_{n}\}\)是等差数列;
              \((2)\)求数列\(\{ \dfrac {1}{a_{n}\cdot a_{n+1}}\}\)的前\(n\)项和\(T_{n}\).
            • 2.
              已知等差数列\(\{a_{n}\}\)的前\(n\)项和为\(s_{n}\),且满足\(a_{3}=6\),\(S_{11}=132\)
              \((1)\)求\(\{a_{n}\}\)的通项公式;
              \((2)\)求数列\(\{ \dfrac {1}{S_{n}}\}\)的前\(n\)项和\(T_{n}\).
            • 3.
              在等差数列\(\{a_{n}\}\)中,\(a_{2}=4\),\(a_{4}+a_{7}=15\).
              \((1)\)求数列\(\{a_{n}\}\)的通项公式;
              \((2)\)设\(b_{n}=2^{a_{n}-2}\),求\(b_{1}+b_{2}+b_{3}+…+b_{10}\)的值.
            • 4.
              等差数列\(\{a_{n}\}\)中,\(a_{2}=5\),\(a_{1}+a_{4}=12\),等比数列\(\{b_{n}\}\)的各项均为正数,且满足\(b_{n}b_{n+1}=2\;^{a_{n}}\)
              \((\)Ⅰ\()\)求数列\(\{a_{n}\}\)的通项公式及数列\(\{b_{n}\}\)的公比\(q\)
              \((\)Ⅱ\()\)求数列\(\{a_{n}+b_{n}\}\)的前\(n\)项和\(S_{n}\).
            • 5.
              已知等差数列\(\{a_{n}\}\)中,\(a_{1}+a_{4}=10\),\(a_{5}=10\).
              \((1)\)求数列\(\{a_{n}\}\)的通项公式;
              \((2)\)已知\(b_{n}= \dfrac {4}{a_{n}a_{n+1}}\),求数列\(\{b_{n}\}\)的前\(n\)项和\(S_{n}\).
            • 6.
              已知数列\(\{a_{n}\}\)是等比数列,首项\(a_{1}=1\),公比\(q > 0\),其前\(n\)项和为\(S_{n}\),且\(S_{1}+a_{1}\),\(S_{3}+a_{3}\),\(S_{2}+a_{2}\)成等差数列.
              \((1)\)求数列\(\{a_{n}\}\)的通项公式;
              \((2)\)若数列\(\{b_{n}\}\)满足\(b_{n}= \dfrac {n}{a_{n}}\),求数列\(\{b_{n}\}\)的前\(n\)项和\(T_{n}\).
            • 7.
              设等差数列\(\{a_{n}\}\)的前\(n\)项和为\(S_{n}\),且\(S_{5}=a_{5}+a_{6}=25\).
              \((\)Ⅰ\()\)求\(\{a_{n}\}\)的通项公式;
              \((\)Ⅱ\()\)若不等式\(2S_{n}+8n+27 > (-1)^{n}k(a_{n}+4)\)对所有的正整数\(n\)都成立,求实数\(k\)的取值范围.
            • 8.
              已知各项均为正数的等比数列\(\{a_{n}\}\),\(a_{3}⋅a_{5}=2\),若\(f(x)=x(x-a_{1})(x-a_{2})…(x-a_{7})\),则\(f{{"}}(0)=(\)  \()\)
              A.\(8 \sqrt {2}\)
              B.\(-8 \sqrt {2}\)
              C.\(128\)
              D.\(-128\)
            • 9.
              已知数列\(\{a_{n}\}\)的前\(n\)项和为\(S_{n}=3^{n}+1\).
              \((1)\)求数列\(\{a_{n}\}\)的通项公式;
              \((2)\)令\(b_{n}= \dfrac {n}{a_{n}}\),求数列\(\{b_{n}\}\)的前\(n\)项和\(T_{n}\).
            • 10.
              若数列\(\{a_{n}\}\)的前\(n\)项和\(S_{n}\)满足\(3S_{n}=1-a_{n}\),\(n∈N^{*}\).
              \((1)\)求数列\(\{a_{n}\}\)的通项公式;
              \((2)\)设\(b_{n}= \dfrac {1}{\log _{2}a_{n}\cdot \log _{2}a_{n+1}}(n∈N^{*})\),求数列\(\{b_{n}\}\)的前\(n\)项和\(T_{n}\).
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