优优班--学霸训练营 > 知识点挑题
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            • 1.
              设\(M⊆N^{+}\),正项数列\(\{a_{n}\}\)的前\(n\)项的积为\(T_{n}\),且\(∀k∈M\),当\(n > k\)时,\( \sqrt {T_{n+k}T_{n-k}}=T_{n}T_{k}\)都成立.
              \((1)\)若\(M=\{1\}\),\(a_{1}= \sqrt {3}\),\(a_{2}=3 \sqrt {3}\),求数列\(\{a_{n}\}\)的前\(n\)项和;
              \((2)\)若\(M=\{3,4\}\),\(a_{1}= \sqrt {2}\),求数列\(\{a_{n}\}\)的通项公式.
            • 2.
              定义\( \dfrac {n}{p_{1}+p_{2}+\cdots +p_{n}}\)为\(n\)个正数\(p_{1}\),\(p_{2}\),\(…\),\(p_{n}\)的“均倒数”,若已知数列\(\{a_{n}\}\)的前\(n\)项的“均倒数”为\( \dfrac {1}{2n+1}\),又\(b_{n}= \dfrac {a_{n}+1}{4}\),则\( \dfrac {1}{b_{1}b_{2}}+ \dfrac {1}{b_{2}b_{3}}+…+ \dfrac {1}{b_{2017}b_{2018}}=\) ______ .
            • 3.
              设\(S_{n}\)为正项数列\(\{a_{n}\}\)的前\(n\)项和,满足\(2S_{n}=a \;_{ n }^{ 2 }+a_{n}-2\).
              \((I)\)求\(\{a_{n}\}\)的通项公式;
              \((II)\)若不等式\((1+ \dfrac {2}{a_{n}+t})\;^{a_{n}}\geqslant 4\)对任意正整数\(n\)都成立,求实数\(t\)的取值范围;
              \((III)\)设\(b_{n}=e\;^{ \frac {3}{4}a_{n}\ln (n+1)}(\)其中\(r\)是自然对数的底数\()\),求证:\( \dfrac {b_{1}}{b_{3}}+ \dfrac {b_{2}}{b_{4}}+..+ \dfrac {b_{n}}{b_{n+2}} < \dfrac { \sqrt {6}}{6}\).
            • 4.
              已知数列\(\{a_{n}\}\)的前\(n\)项和\(S_{n}=k(3^{n}-1)\),且\(a_{3}=27\).
              \((1)\)求数列\(\{a_{n}\}\)的通项公式;
              \((2)\)若\(b_{n}=\log _{3}a_{n}\),求数列\(\{ \dfrac {1}{b_{n}b_{n+1}}\}\)的前\(n\)项和\(T_{n}\).
            • 5.
              正项数列\(\{a_{n}\}\)的前\(n\)项和\(S_{n}\)满足:\(S_{n}^{2}-(n^{2}+n-1)S_{n}-(n^{2}+n)=0\)
              \((1)\)求数列\(\{a_{n}\}\)的通项公式\(a_{n}\);
              \((2)\)令\(b\;_{n}= \dfrac {n+1}{(n+2)^{2}a_{n}^{2}}\),数列\(\{b_{n}\}\)的前\(n\)项和为\(T_{n}.\)证明:对于任意\(n∈N^{*}\),都有\(T\;_{n} < \dfrac {5}{64}\).
            • 6.
              已知数列\(\{a_{n}\}\)的前\(n\)项和为\(S_{n}\),且\(S_{n}=2a_{n}-2(n∈2N^{*}).\)
              \((1)\)求数列\(\{a_{n}\}\)的通项公式;
              \((2)\)求数列\(\{S_{n}\}\)的前\(n\)项和\(T_{n}\).
            • 7. 已知在等差数列{an}中,a3=4前7项和等于35,数列{bn}中,点(bn,sn)在直线x+2y-2=0上,其中sn是数列{bn}的前n项和(n∈N*).
              (1)求数列{an}的通项公式;
              (2)求证:数列{bn}是等比数列;
              (3)设cn=an•bn•Tn为数列{cn}的前n项和,求Tn并证明;≤Tn
            • 8. 在数列{an}中,a1=1,a2=2,且an+1=(1+q)an-qan-1(n≥2,q≠0).
              (Ⅰ)设bn=an+1-an(n∈N*),证明{bn}是等比数列;
              (Ⅱ)求数列{an}的通项公式;
              (Ⅲ)若a3是a6与a9的等差中项,求q的值,并证明:对任意的n∈N*,an是an+3与an+6的等差中项.
            • 9. 在数列{an}中,a1=1,当n≥2时,其前n项和Sn满足
              (1)求an
              (2)令,求数列{bn}的前项和Tn
            • 10. 已知各项均为正数的两个数列{an}和{bn}满足:an+1=,n∈N*
              (1)设bn+1=1+,n∈N*,,求证:数列是等差数列;
              (2)设bn+1=,n∈N*,且{an}是等比数列,求a1和b1的值.
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