优优班--学霸训练营 > 知识点挑题
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            • 1.
              如图,四棱锥\(P-ABCD\)的底面\(ABCD\)为菱形,\(PA⊥\)平面\(ABCD\),\(PA=AB=2\),\(E\)、\(F\)分别为\(CD\)、\(PB\)的中点,\(AE= \sqrt {3}\).
              \((\)Ⅰ\()\)求证:平面\(AEF⊥\)平面\(PAB\).
              \((\)Ⅱ\()\)求平面\(PAB\)与平面\(PCD\)所成的锐二面角的余弦值.
            • 2.
              如图,已知四棱锥\(P-ABCD\),底面\(ABCD\)是边长为\(2\)的菱形,\(PA⊥\)平面\(ABCD\),\(∠ABC=60^{\circ}\),\(E\)、\(F\)分别是\(BC\)、\(PC\)的中点.
              \((1)\)证明:\(AE⊥PD\);
              \((\)Ⅱ\()\)若\(PA=AB\),求二面角\(E-AF-C\)的余弦值.
            • 3.

              在正方体\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,\(E\)是\(AD\)的中点,则异面直线\(C_{1}E\)与\(BC\)所成的角的余弦值是\((\)  \()\)
              A.\( \dfrac { \sqrt {10}}{5}\)
              B.\( \dfrac { \sqrt {10}}{10}\)
              C.\( \dfrac {1}{3}\)
              D.\( \dfrac {2 \sqrt {2}}{3}\)
            • 4.
              如图,四边形\(ABCD\)为正方形,\(PD⊥\)平面\(ABCD\),\(PD/\!/QA\),\(QA=AB= \dfrac {1}{2}PD\).
              \((\)Ⅰ\()\)证明:平面\(PQC⊥\)平面\(DCQ\)
              \((\)Ⅱ\()\)求二面角\(Q-BP-C\)的余弦值.
            • 5.
              在正方体\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,\(E\)是\(C_{1}C\)的中点,则直线\(BE\)与平面\(B_{1}BD\)所成的角的正弦值为\((\)  \()\)
              A.\(- \dfrac { \sqrt {10}}{5}\)
              B.\( \dfrac { \sqrt {10}}{5}\)
              C.\(- \dfrac { \sqrt {15}}{5}\)
              D.\( \dfrac { \sqrt {15}}{5}\)
            • 6.
              如图,\(ABCD\)是边长为\(3\)的正方形,\(DE⊥\)平面\(ABCD\),\(AF/\!/DE\),\(DE=3AF\),\(BE\)与平面\(ABCD\)所成角为\(60^{\circ}\).
              \((\)Ⅰ\()\)求证:\(AC⊥\)平面\(BDE\);
              \((\)Ⅱ\()\)求二面角\(F-BE-D\)的余弦值.
            • 7.
              如图\(\triangle BCD\)与\(\triangle MCD\)都是边长为\(2\)的正三角形,平面\(MCD⊥\)平面\(BCD\),\(AB⊥\)平面\(BCD\),\(AB=2 \sqrt {3}\).
              \((1)\)求点\(A\)到平面\(MBC\)的距离;
              \((2)\)求平面\(ACM\)与平面\(BCD\)所成二面角的正弦值.
            • 8.
              如图,在四棱柱\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,\(AA_{1}⊥\)平面\(ABCD\),\(AB/\!/CD\),\(AB⊥AD\),\(AD=CD=1\),\(AA_{1}=AB=2\),\(E\)为\(AA_{1}\)的中点.
              \((\)Ⅰ\()\)求四棱锥\(C-AEB_{1}B\)的体积;
              \((\)Ⅱ\()\)设点\(M\)在线段\(C_{1}E\)上,且直线\(AM\)与平面\(BCC_{1}B_{1}\)所成角的正弦值为\( \dfrac {1}{3}\),求线段\(AM\)的长度;
              \((\)Ⅲ\()\)判断线段\(B_{1}C\)上是否存在一点\(N\),使得\(NE/\!/CD\)?\((\)结论不要求证明\()\)
            • 9.
              如图,在三棱锥\(S-ABC\)中,\(SB⊥\)底面\(ABC\),且\(SB=AB=2\),\(BC= \sqrt {6},∠ABC= \dfrac {π}{2}\),\(D\)、\(E\)分别是\(SA\)、\(SC\)的中点.
              \((I)\)求证:平面\(ACD⊥\)平面\(BCD\);
              \((II)\)求二面角\(S-BD-E\)的平面角的大小.
            • 10.
              如图,已知矩形\(ABCD\)所在平面垂直于直角梯形\(ABPE\)所在平面,平面\(ABCD∩\)平面\(ABPE=AB\),且\(AB=BP=2\),\(AD=AE=1\),\(AE⊥AB\),且\(AE/\!/BP\).
              \((\)Ⅰ\()\)设点\(M\)为棱\(PD\)中点,求证:\(EM/\!/\)平面\(ABCD\);
              \((\)Ⅱ\()\)线段\(PD\)上是否存在一点\(N\),使得直线\(BN\)与平面\(PCD\)所成角的正弦值等于\( \dfrac {2}{5}\)?若存在,试确定点\(N\)的位置;若不存在,请说明理由.
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